28x^2-56x+1=0

Solution for 28x^2-56x+1=0 equation:

28x^2-56x+1=0

a = 28; b = -56; c = +1;
Δ = b2-4ac
Δ = -562-4·28·1
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-12\sqrt{21}}{2*28}=\frac{56-12\sqrt{21}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+12\sqrt{21}}{2*28}=\frac{56+12\sqrt{21}}{56}
$